(Q17) In the given figure, AC = 6 cm, AB = 5 cm and ∠BAC = 30o. Find the area of the triangle.

ABC6cm5cm30o

Solution :

ABCDx6-x530o

Draw a perpendicular BD to AC

∴ BD ⊥ AC

Now let AD = 6 - x and DC = x

Given AB = 5 cm and ∠BAD = 30° then in ∆ABD

sin ° =
BD
AB
=
BD
=
1
BD =
= cm
and cos ° =
AD
AB
=
6 - x
=
6 - x =

x = 6 -

∴ x = .67

∴ Area of ∆ABC =
1
2
bh
=
1
2
× ×
=
1
2
× × = cm2